Atown has 685 households. the number of people per household is normally distributed with the mean of 3.67 and the standard deviation of 0.34. approximately how many households have between 2.99 and 4.01

560 households.  

Step-by-step explanation:

We have been given that a town has 685 households. the number of people per household is normally distributed with the mean of 3.67 and the standard deviation of 0.34.

Let us find z-score corresponding to sample scores, 2.99 and 4.01, using z-score formula.

, where,

,

,

,

.

Let us find z-score for sample score 2.99.

Let us find z-core for sample score 4.01.

Now let us find probability of z-score greater than -2 and z-score less than 1.

We will use formula: to solve our problem.

Using normal distribution table we will get,

So, the probability of house holds between 2.99 and 4.01 is 0.81859. To find the number of households between 2.99 and 4.01, we will multiply our probability by total number of households.

Therefore, approximately 560 households have between 2.99 and 4.01.

let soccer = x and golf = y

part a

1st equation: x + y = 125

2nd equation: x = y +45

part b

replace x in the 1st equation with the 2nd one:

y + 45 + y = 125

simplify:

2y + 45 = 125

subtract 45 from each side:

2y = 80

divide both sides by 2:

y = 80/2

y = 40

she plays golf for 40 minutes.

part c

no because she plays soccer for 45 minutes longer than golf 40 +45 =   85 minutes, not 80 minutes.

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's