The vertices of a triangle are a(8,-24) b(8,-8) and c(16,-8). if the triangle was dilated by a scale factor of 1/4, what would the coordinates of a’ be?

A' (2,-6)

Step-by-step explanation:

1. The problem gives you the coordinates of the vertex A, which is:

A(8,-24)

2. Then, to solve the problem and obtain the coordinates of of the vertex A', you must multiply the coordinates of the vertex A by the given scale factor 1/4, as you can see below:

8*1/4=8/4=2

-24*1/4=-24/4=-6

3. Therefore, the coordinates of of the vertex A' would be:

A'(2,-6)

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²

a) 0

step-by-step explanation:

i^413 x i^0 = 0 as any number multiplied by a zero is

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