Triangle xyz with vertices x(0,0) , y(0,-2) , z(-2,-2) is rotated to create the image triangle x’(0,0) , y’(2,0) , z’(2,-2).

which rules could describe the rotation ?

[]r 0,90
[]r 0,180
[]r 0,270
[](x, y) -> (-y, x)
[](x, y) -> (y,-x)

The correct options are

R 0,90,

R 0,270,

(x,y) -> (-y,x)

Step-by-step explanation:

In R 0,90,

Thus, If the triangle XYZ with vertices X(0,0) , Y(0,-2) , Z(-2,-2) is rotated 90° about origin,

Then its new coordinates are,

Thus, If X'Y'Z' is the transformed triangle the coordinates of the transformed figure,

X'(0,0) , Y’(2,0) , Z’(2,-2).

⇒ First Option is correct.

In R 0,180,

Thus, If the triangle XYZ with vertices X(0,0) , Y(0,-2) , Z(-2,-2) is rotated 90° about origin,

Then its new coordinates are,

Thus, If X'Y'Z' is the transformed triangle the coordinates of the transformed figure,

X'(0,0) , Y’(0,2) , Z’(2, 2).

⇒ Second option is incorrect.

In R 0,270,

Thus, If the triangle XYZ with vertices X(0,0) , Y(0,-2) , Z(-2,-2) is rotated 90° about origin,

Then its new coordinates are,

Thus, If X'Y'Z' is the transformed triangle the coordinates of the transformed figure,

X'(0,0) , Y’(2,0) , Z’(2,-2).

⇒ Third Option is correct.

In (x,y) -> (-y,x)

The new coordinates are,

Thus, If X'Y'Z' is the transformed triangle the coordinates of the transformed figure,

X'(0,0) , Y’(2,0) , Z’(2,-2).

⇒Fourth Option is correct.

In (x,y) -> (y,-x)

The new coordinates are,

Thus, If X'Y'Z' is the transformed triangle the coordinates of the transformed figure,

X'(0,0) , Y’(2,0) , Z’(-2,2).

⇒Fourth Option is incorrect.

R 0,90,

R 0,270,

(x,y) -> (-y,x)

Step-by-step explanation:

range is infinite on both x and y axis positive and negative

step-by-step explanation:

sorry i need the points

step-by-step explanation:

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