Express y=-2x^2-5x-18 as y=a(x-p)(x-q), where a, h, and k are constants. hence state the equation of the line of symmetry and hence find the minimum value of y.

need it quick , 20 points ! : )

y = -2·x^2 - 5·x - 18

y = -2·(x^2 + 10·x + 36)

y = -2·(x^2 + 10·x + 36)

y = -2·(x - (-5 - √11·i))·(x - (-5 + √11·i))

Maybe there is a typo in the original question, because there is no factorisation in the real numbers.

Because the question is " find the minimum value of y" the coefficient before x^2 must be a positive number. so it could be

y = 2·x^2 - 5·x - 18

Can you check this out?

-232

step-by-step explanation:

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