![\text{Use}\\\\(a^n)^m=a^{nm}\\\\a^n\cdot a^m=a^{n+m}\\\\(a\cdot b)^n=a^n\cdot b^n\\\\a^{-1}=\dfrac{1}{a}\\--------------------------\\\\\dfrac{5^{2n-1}-4(25^{n-1})}{(5^n\cdot2)^2+3(5^{2n-1})}=\dfrac{5^{2n}\cdot5^{-1}-4\left[(5^2)^n\cdot25^{-1}\right]}{(5^n)^2\cdot2^2+3\left[(5^2)^n\cdot5^{-1}\right]}](/tpl/images/0498/1605/7b35a.png)
Pls me answer this question thx
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Mathematics, 03.02.2020 22:59 thomaswillmsn7496
Pls me answer this question thx
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