What is the surface area of this triangular prism rounded to the nearest tenth? a) 18.5 m2 b) 36.9 m2 c) 43.6 m2 d) 87.2 m2.

length: 5.3 height: 1.26 width: 3.3

Answer the answer is D it’s the answer because I took the test and assignment

Step-by-step explanation:

The answer is 43.6 m2

Step-by-step explanation:

SA = bh + (s1 + s2 + s3)H

SA = (5.3)(1.26) + (5.3 + 3.6 + 2.3)(3.3) = 43.638

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation: