What proportional segment lengths verify that bc∥de ? fill in the boxes to correctly complete the proportion. $$ = $$ a triangle with vertices labeled as a, b, c. side b c is base. sides a b and a c contain midpoints d and e, respectively. a line segment is drawn from d to e. side a d is labeled as 4. side d b is labeled as 6. side a e is labeled as 3.2. side e c is labeled as 4.8.

Step-by-step explanation:

Given,

ABC is a triangle,

In which, AD = 4 unit, DB = 6 unit, AE = 3.2 unit and EC = 4.8 unit,

⇒  

⇒ Δ ADE  ≅  Δ ABC  

⇒ ∠ADE ≅ ∠ABC  and ∠AED ≅ ∠ACB

By the converse of alternate interior angle theorem.

BC ║ DE

Hence, the required proportion of segment is,

$53.50

step-by-step explanation:

you have to subtract the amount of money chuck earned ($72.50) by the cost of the gas for the mower ($11.25) and the new string for the trimmer he bought ($7.75).

72.50-11.25=61.25

and then subtract $61.25 by the second thing he bought (the new string for the trimmer)

61.25-7.75=53.5

so in total it's $53.50 (53 dollars and 50 cents)

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°