1.)solve the inequality. graph the solution.

−r3≤6

the solution is.

2.)solve the inequality. graph the solution.

−4> −43s

the solution is.

3.)solve the inequality. graph the solution.

z−2−6≤−2

the solution is.

4.)solve the inequality. graph the solution.

−2t−5< 9

the solution is.

5.)solve the inequality. graph the solution.

7(q+2)< −77

the solution is.

5.)solve the inequality. graph the solution.

−13(p+9)≤4

the solution is.

6.)solve the inequality. graph the solution.

1.2(j+3.5)≥4.8

the solution is.

me : (

Part 1)

Part 2)    

Part 3)

Part 4)  

Part 5)

Part 6)

Step-by-step explanation:      

Part 1)            

Multiply by -1 both sides

The solution is the interval -------> [-1.817,∞)

The solution in the attached figure N 1    

Part 2)      

rewrite

Multiply by -1 both sides

The solution is the interval--------> (0.09,∞)

The solution in the attached figure N 2

Part 3)

combine like terms

Adds 8 both sides

The solution is the interval--------> (-∞,6]

The solution in the attached figure N 3  

Part 4)    

Adds 5 both sides

Multiply by -1 both sides

Divide by 2 both sides

The solution is the interval--------> (-7,∞)

The solution in the attached figure N 4  

Part 5)

applying distributive property left side

Subtract 14 both sides

Divide by 7 both sides

The solution is the interval--------> (-∞,-13)

The solution in the attached figure N 5

Part 6)

applying distributive property left side

Adds 117 both sides

Divide by -1 both sides

Divide by 13 both sides

The solution is the interval--------> [-9.31,∞)  

The solution in the attached figure N 5

step-by-step explanation:

a cube has 6 sides

the probability of getting 5 on the first cube is 1/6 since only one side of the cube has 5 on it.

there are 3 sides of the cube with even number on it [2,4,6]

therefore the probability of getting even number is 3/6

for both events to happen together, the probability would be

1/6 x 3/6 = 12/36

which simplifies to 1/12

the answer is  

a.

4,624π mm2

step-by-step explanation: