Can someone show work for these problems will give ! emergency

Part 1)

Part 2)  

Part 3)

Part 4)  

Part 5)

Part 6)  

Part 7)  

Part 8)

Part 9)

Part 10)

Part 11)

Part 12)

Step-by-step explanation:

Part 1)  

Subtract 4 both sides

Divide by 2 both sides

the solution is the interval ------> [10,∞)

The solution is the shaded area to the right of the solid line at number 10 (closed circle).

see the attached figure  

Part 2)  

Adds 3 both sides

Multiply by 3 both sides

the solution is the interval ------> (-∞,-9]

The solution is the shaded area to the left of the solid line at number -9 (closed circle).

see the attached figure  

Part 3)  

applying the distributive property left side

adds 3 both sides

Multiply by -1 both sides

Divide by 3 both sides

the solution is the interval ------> [5,∞)

The solution is the shaded area to the right of the solid line at number 5 (closed circle).

see the attached figure

Part 4)  

applying the distributive property left side  

Subtract 16 both sides  

Multiply by -1 both sides

Divide by 4 both sides

the solution is the interval ------> (-∞,-10)

The solution is the shaded area to the left of the dashed line at number -10 (open circle).

see the attached figure

Part 5)

adds 2 both sides

Multiply by -1 both sides

the solution is the interval ------> (-∞,-10)

The solution is the shaded area to the left of the dashed line at number -10 (open circle).

Part 6)

applying the distributive property left side  

adds 12 both sides

multiply by -1 both sides

divide by 4 both sides

the solution is the interval ------> (-∞,5)

The solution is the shaded area to the left of the dashed line at number 5 (open circle).

see the attached figure

Part 7)

Subtract 4 both sides

Multiply by 3 both sides

the solution is the interval ------> (-∞,6)

The solution is the shaded area to the left of the dashed line at number 6 (open circle).

see the attached figure  

Part 8)

applying the distributive property left side

subtract 12 both sides

divide by -1 both sides

divide by 3 both sides

the solution is the interval ------> (-∞,4]

The solution is the shaded area to the left of the solid line at number 4 (closed circle).

see the attached figure  

Part 9)  

Adds 7 both sides

Multiply by -1 both sides

Divide by 7 both sides

the solution is the interval ------> [7,∞)

The solution is the shaded area to the right of the solid line at number 7 (closed circle).

see the attached figure  

Part 10)  

applying the distributive property left side

subtract 21 both sides

Multiply by -1 both sides

the solution is the interval ------> (-∞,0]

The solution is the shaded area to the left of the solid line at number 0 (closed circle).

see the attached figure  

Part 11)  

Adds 4 both sides

Multiply by -1 both sides

Divide by 11 both sides

the solution is the interval ------> (-∞,1)

The solution is the shaded area to the left of the dashed line at number 1 (open circle).

see the attached figure

Part 12)  

Multiply by 15 both sides

Adds 9 both sides

the solution is the interval ------> (24,∞)

The solution is the shaded area to the right of the dashed line at number 24 (open circle).

see the attached figure

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

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step-by-step explanation:

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