x = 1; x = 8
Step-by-step explanation:
This is late but I suppose it'll come to use later for some other k12 kid. For the second problem, you'll wanna divide everything by 4 first just to make things easier.
4x^2 / 4 -36x/4 32/4 = 0/4
This would equal to: x^4 - 9 + 8 = 0
Then, find two numbers that multiply to make 8, but add to make -9. (If that makes sense...forgot the name of the rule.)
List the factors of 8 and see what you're working with.
1, 8
-1, -8
2, 4
-2, -4
-1 and -8 multiply to make 8 and add to make -9. (-1 - 8 = -9); (-1 * -8 = 8)
Now we can plug this into the equation. (x - 1) (x - 8) = 0
So, x - 1 = 0 and x - 8 = 0
Now simplify: x = 1; x = 8