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at an ocean depth of 8 meters, a buoy bobs up and then down 5 meters from the ocean's depth. sixteen seconds pass from the time the buoy is at its highest point to when it is at its lowest point. assume at x = 0 the buoy is at normal ocean depth.

use the sine tool to graph the function. the first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.

Answer with explanation:

It is given that:

At an ocean depth of 8 meters, a buoy bobs up and then down 5 meters from the ocean's depth.

Sixteen seconds pass from the time the buoy is at its highest point to when it is at its lowest point.

Assume at x = 0 the buoy is at normal ocean depth.

this means that when x=0 the value on the y-axis is -8.

Also, the buoy bobs up 5 meters up so the maximum height reached by him is -3.

( Since -8+5=-3)

So, the sine function that will represent this situation  is:

Now, the graph of this situation is attached to the answer and the mid-line and the first and the second points on it are labelled.

answer: i think it is (1,-2)

answer: a.

step-by-step explanation: the answer is a. because, you need to converge the fractions to find a solution.