Find the value of x in pythagorean theorem.

Hello from MrBillDoesMath!

x = 21.93   (approx)

Discussion:

The two small triangles are congruent by ASA (each contains a right angle and equal base angles as the large triangle is isosceles). Applying Pythagoras gives

20^2 + (18/2)^2 = x^2                = > as 20^2 = 400 and 9^2 = 81

400   + 81           = x^2               =>

x^2 = 481                                    => take the square rot of both sides

x = 21.93   (approx)

Thank you,

MrB

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.