Find the value of tan theta if sin theta = 12/13 and theta is in quadrant 2

اhello : tan θ = - 12/5

Step-by-step explanation:

tan θ = sin θ / cos θ (*)

(cosθ)² + (sinθ)² = 1   ... (**)

theta is in quadrant 2 : cosθ ≤ 0

Substitute sinθ = 12/13  into (**) and solve for cosθ :

(cosθ)² + (12/13)² = 1  

(cosθ)²  = 1   - 144/169

(cosθ)²  = 25/169

cosθ = - 5 /13  because  cosθ ≤ 0

by (*) : tan θ = (12/13)/ (-5/13) = (12/13) ×(-13/5)

tan θ = - 12/5

you answer is a

step-by-step explanation:

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.