Lee has $1.75 in dimes and nickels. the number of nickels is 11 more than the number of dimes. how many of each coin does he have?

Lee has 19 nickels and 8 dimes

Step-by-step explanation:

hello, I think I can help you with this

Step 1

Let

value of a nickel=$0.05

value of a dime=$0.10

number of nickels=N

number of nickels=D

According to the question data Lee has $1.75 in dimes and nickels.

0.05N+0.1D=1.75,equation(1)

also, the number of nickels is 11 more than the number of dimes.mathematical speaking

N=11+D,equation(2)

Step 2

replace N from equation (2) into equation (1)

0.05N+0.1D=1.75

0.05(11+D)+0.1D=1.75

Now, solve for D

0.55+0.05D+0.1D=1.75

0.15D=1.75-0.55

D=1.2/0.15

D=8

Step 3

replace the value of D into equation(2) to obtain N

N=11+8

N=11+8

N=19

Hence, Lee has 19 nickels and 8 dimes

Have a great day.

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1