Ineed to know the answer to this algebra question.

x=2 is not a solution

Step-by-step explanation:

x^4 +2x^3 -x^2 -2x = 0

I will factor by grouping

x^4 -x^2  +   2x^3 -2x =0

Factor out x^2 from the first group and 2x from the second group

x^2(x^2-1) +2x(x^2-1) =0

Now factor out x^2-1

(x^2-1) (x^2+2x)=0

From the second term we can factor out an x

(x^2-1) x(x+2)=0

Using the zero product property

(x^2-1) =0     x = 0    (x+2)=0

x^2 =1             x=0          x=-2

Taking the square root

x=±1                x=0               x= -2

The solutions are -2,-1,0,1

idk

step-by-step explanation: