If x-1 and x+3 are the factors of x3+10x2+ax+b find a and b

hello : b = -24  and  a =13

Step-by-step explanation:

let : f(x) = x3+10x2+ax+b

( x - 1  ) and  ( x+3) are the factors  

so : 1 and - 3 are the zeros  of x3+10x2+ax+b

f(1) = 0 and f(-3) = 0

f(1) = 0       :    1^3 + 10 (1)² + a(1) + b =0

a + b + 11 = 0 ......(*)

f(-3) = 0     : (-3)^3 +10(-3)² +a(-3) +b = 0....but (-3)^3 +10(-3)² = -27+90 = 63

- 3a + b + 63 = 0 ......(**)

(*) - (**) ; a + b + 11 +3a -b - 63 =0

4a = 52

a = 13

subsct(*)  in :  13 + b  +11 = 0

b = - 24

second solution:  look here

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.

step-by-step explanation: