The points (1, 7) and (0, 2) fall on a particular line. what is its equation in slope-intercept form?

Slope-intercept form is y = mx + b

So we can manage to do this:

(y - yo) = m.(x - xo)

Where (x, y) and (xo, yo) are points of this line, this way we can discover the slope.

(7 - 2) = m.(1 - 0)

5 = m

m = 5

So,

y = 5x + b

Now we still have to use (y - yo) = m.(x - xo), but this time we will put only 1 point and the slope.

(y - yo) = m.(x - xo)

(y - 2) = 5.(x - 0)

y - 2 = 5x

y = 5x + 2

So, this is the line in slope-intercept form.

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4

x-150=475   x=625

step-by-step explanation:

if the bike after the sale ($150) is $475 then just simply add 150 to 475.