When a 757 passenger jet begins its descent to the ronald reagan national airport in washington, d. c., it is 3900 feet from the ground. its angle of descent is 6 degrees. how far must the plane fly to reach the run way? a. 37,106 ft b. 37,310.4 ft c. 23,456.6 ft d 2,492.7 ft

Option A. 37106 ft.

Step-by-step explanation:

Given: An 757 passenger jet at the height of 3900 feet from the ground means vertical height = 3900 feet.

Angle of descent to the airport in Washington,D.C. is 6 degrees.

To find: Horizontal distance the plane will cover to reach the run way.

Solution: As we know tan ∅  =

Then tan 6° =

0.105 =

x =

x = 37106 ft

use this formula:

p(a\b) = p(a and b)/p(b).

take it from here.

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation: