Atriangular prism has a volume of 240 cubic meters which of the measurements below are not possible dimensions for the area of the base and the height of the prism

I) B = 20 m², h = 4 m are NOT possible dimensions for the area of the base and the height of the prism.

Step-by-step explanation:

Given that the triangular prism has a volume = 240 m³, we can use the formula for the volume of a triangular prism to check the given answers for possible dimensions.  V = Bh, where B = the area of the base and h = height of the prism.  In this case, we simply need to multiply each of the given dimensions together to see if they equal 240 m³:

F) B = 48 m², h = 5 m:  v = 48 x 5 = 240 m³ (possible)

G) B = 24 m², h = 10 m; v = 24 x 10 = 240 m³ (possible)

H) B = 12 m², h = 20 m: v = 12 x 24 = 240 m³ (possible)

I) B = 20 m², h = 4 m: v = 20 x 4 = 80 m³ (NOT possible)

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

168

step-by-step explanation:

i am pretty sure that the answer is 168