Former nfl punter ray guy holds the record for the longest hangtime on a punt. if the ball leaves with an upward velocity of 128 ft/s from an initial height of 4 feet, how long will the ball be in the air? use the formula where h is the height of the ball in feet and t is the time in seconds since it is kicked. round your answer to the nearest tenth.

The correct option is D.

Step-by-step explanation:

The given equation

Where,  h is the height of the ball in feet and t is the time in seconds since it is kicked.

The leading coefficient is negative, so it is a downward parabola.

First of all find zeros of given function.

Using quadratic formula we get

So the ball is in the air between t=-0.031 and t=8.031. Since the time can not be negative, therefore the ball is in the air between t=0 and t=8.031.

The ball is in the air for 8.031 second, so option D is correct.

for finding the midpoint of any given 2 pair of points simply add the respective x coordinates with other x coordinate and the y coordinate with other y coordinate and divide them by 2

in your question it will be :

(3+1)/2 for the x coordinate of mid point i.e 2

[8+(-4)]/2 for the y coordinate of midpoint i.e 2

so coordinates of mid point of points (3,8) and (1,-4) will be (2,2)