Hurry will give brainliest a truck can be rented from company a for $90 a day plus $0.30 per mile. company b charges $70 a day plus $0.80 per mile to rent the same truck. find the number of miles in a day at which the rental cost for company a and company b are the same

  40 miles a day

Step-by-step explanation:

The difference in fixed charge is $20; the difference in mileage charge is $0.50 per mile. So it will take $20/$0.50 = 40 miles for the extra mileage cost to eat up the savings in fixed cost. At that mileage, both companies will charge the same amount:

  A: 90 + 0.30·40 = 102

  B: 70 + 0.80·40 = 102

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube

b

step-by-step explanation:

multiply terms on numerator/ denominator by (x - 1)

= ← distribute numerator/ denominator

= ← simplify

=

= → b