Paul and darry are selling fruit for a school fundraiser. customers can buy small boxes of grapefruit. paul sold 5 boxes of grapefruit and 8 boxes of grapefruit for a total of $115. darry sold 6 small boxes of grapefruit and 5 large boxes of grapefruit for a total of $92. what is the cost of each of one small box of grapefruit and 5 large box of grapefruit? solve by using elimination or substitution show all work . cpa2 math heres the 2 equations i got 5x+8y=115 and 6x+5y=92i have been stuck on this 4 days

57

Step-by-step explanation:

5x+8y=115

6x+5y=92

We can either use substitution or elimination.  I prefer elimination

Multiply the first equation by 6  and the second equation by -5 to eliminate x

6(5x+8y)=115*6

30x +48y = 690

The second equation

-5( 6x+5y)=92*-5

-30x -25y =-460

Add the two equations together

30x +48y = 690

-30x -25y =-460

       23y =  230

Divide each side by 23

23y/23 = 230/23

y = 10

Now we need to find x

6x+5y=92

6x+5(10) = 92

6x+50 =92

Subtract 50 from each side

6x +50-50 = 92-50

6x = 42

Divide by 6

6x/6 = 42/6

x = 7

We want to find the cost of 1  small grapefruit and  5 large grapefruit

x +5y

7 + 5(10)

7+50

57

answer: idk

step-by-step explanation:

shell's the art director at her local community center. she paid $10 and for each child that attends she earns $4.

for each child she ears $4 that is the slope m = 4

she paid $10, that is the initial amount paid. so 10 is the y intercept b

m =4   and b = 10

y intercept is 10 so the point is (0,10)

we start graph from y intercept (0,10)

slope = 4 . we know slope = rise / run

slope = 4   or 4/1   are same

rise = 4   and run = 1

for rise we move 4 units up and for run we move 1 unit to the right

the graph is attached below

x axis is the number of child she attends

y axis is the amount   she earns