Determine the zeros and state the multiplicity of any repeated zeros for f(x)=3x(x+2)^2(2x-1)^3

see explanation

Step-by-step explanation:

To determine the zeros of f(x) equate f(x) = 0, that is

3x(x + 2)²(2x - 1)³ = 0

Equate each factor to zero and solve for x

3x = 0 ⇒ x = 0 with multiplicity 1

(x + 2)² = 0 ⇒ x = - 2 with multiplicity 2

(2x - 1)³ = 0 ⇒ x = with multiplicity 3

depends on how many days you are talking about

step-by-step explanation:

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.