Which line is perpendicular to y = 2x -8 a. 4y = - 2x +2 b. y = 2x - 4 c. 3x + 2y = -6 d. y = - 2x + 7

Choice A is correct answer.

Step-by-step explanation:

We have to find a equation of line which is perpendicular to y=2x-8.

The slope of perpendicular lines are negative reciprocals of each other.

y=mx+c is standard form of equation of line where m is slope and c is y-intercept.

given equation is :

y=2x-8

Compare above equation with standard form of equation of line,we get

m=2

The slope of perpendicular lines are negative reciprocals of each other.

Hence,  m=-1/2

4y=-2x+2

dividing by 4 to both sides of above equation ,we get

Choice A is:

4y/4=-2x+2/4

y=-2/4x+2/4

y=-1/2x+1/2

hence,choice A has slope equal to -1/2.

4y=-2x+2 is equatio of line perpendicular to y=2x-8.

So,choice A is the answer.

8y^50

step-by-step explanation: