 # Using only the values given in the table for the function f(x) = –x3 + 4x + 3, what is the largest interval of x-values where the function is increasing? step-by-step explanation:

do you have a copy of the table? [-1, 1]

Step-by-step explanation:

just did this [-1, 1]

Step-by-step explanation:

Comparing each table value to the one before, we find the function to be increasing on the interval [-1, 1].

__

The graph in the second attachment shows that integer interval to be the only one where the function is increasing.   (-1, 1)

Just got done with edge the largest interval of x values where f(x) is increasing is (-1,1).

Step-by-step explanation: the domain of  f(x) is all real numbers.

As we can conclude from the table that the function f(x) is decreasing from (-3, -1) and the function is increasing from (-1, 1) .

Graphically we can also show this that for the x-values in  (1,-1) function is increasing. I assume you mean -x^3 + 4x + 3
so what you need is 4x + 3 > x^3
the only whole number it could be is 2 because 2x2x2 +3 > 2x2x2 is -1 and 1 in e2020  The values are the given below:

Table

x           f(x) = - x^3 + 4x + 3

-3          -(-3)^3 + 4(-3) + 3 = 27 - 12 + 3 = 18

-2         -(-2)^3 + 4(-2) + 3 = 8 - 8 + 3 = 3

-1         -(-1)^3 + 4(-1) + 3 = 1 - 4 + 3 = 0

0           0^3 + 4(0) + 3 = 3

1           -(1)^3 + 4(1) + 3 = - 1 + 4 + 3 = 6

2           -(2)^3 + 4(2) + 3 = -8 + 8 + 3 = 0

So, the interval in which the values are increasing is (-1,1), because the function increases from 0 to 3 to 6.

(-1,1) The answer is -1 and 1 in E2020

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Using only the values given in the table for the function f(x) = –x3 + 4x + 3, what is the largest i...

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