Mathematics, 22.06.2019 21:00 emilyask

# Using only the values given in the table for the function f(x) = –x3 + 4x + 3, what is the largest interval of x-values where the function is increasing?

Answer from: vandonquisenberry

[-1, 1]

Step-by-step explanation:

Comparing each table value to the one before, we find the function to be increasing on the interval [-1, 1].

__

The graph in the second attachment shows that integer interval to be the only one where the function is increasing.

Answer from: jdjxbxnshd2080

the largest interval of x values where f(x) is increasing is (-1,1).

Step-by-step explanation:

the domain of f(x) is all real numbers.

As we can conclude from the table that the function f(x) is decreasing from (-3, -1) and the function is increasing from (-1, 1) .

Graphically we can also show this that for the x-values in (1,-1) function is increasing.

Answer from: rubincain698

I assume you mean -x^3 + 4x + 3

so what you need is 4x + 3 > x^3

the only whole number it could be is 2 because 2x2x2 +3 > 2x2x2

so what you need is 4x + 3 > x^3

the only whole number it could be is 2 because 2x2x2 +3 > 2x2x2

Answer from: cxm

The values are the given below:

Table

x f(x) = - x^3 + 4x + 3

-3 -(-3)^3 + 4(-3) + 3 = 27 - 12 + 3 = 18

-2 -(-2)^3 + 4(-2) + 3 = 8 - 8 + 3 = 3

-1 -(-1)^3 + 4(-1) + 3 = 1 - 4 + 3 = 0

0 0^3 + 4(0) + 3 = 3

1 -(1)^3 + 4(1) + 3 = - 1 + 4 + 3 = 6

2 -(2)^3 + 4(2) + 3 = -8 + 8 + 3 = 0

So, the interval in which the values are increasing is (-1,1), because the function increases from 0 to 3 to 6.

(-1,1)

Table

x f(x) = - x^3 + 4x + 3

-3 -(-3)^3 + 4(-3) + 3 = 27 - 12 + 3 = 18

-2 -(-2)^3 + 4(-2) + 3 = 8 - 8 + 3 = 3

-1 -(-1)^3 + 4(-1) + 3 = 1 - 4 + 3 = 0

0 0^3 + 4(0) + 3 = 3

1 -(1)^3 + 4(1) + 3 = - 1 + 4 + 3 = 6

2 -(2)^3 + 4(2) + 3 = -8 + 8 + 3 = 0

So, the interval in which the values are increasing is (-1,1), because the function increases from 0 to 3 to 6.

(-1,1)

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Using only the values given in the table for the function f(x) = –x3 + 4x + 3, what is the largest i...

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