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Mathematics, 22.06.2019 21:00 reyrey216

If an object is projected upward with an initial velocity of 126ft per? sec, its height h after t seconds is h=? 16t^2+126t. find the height of the object after 4 seconds

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Answer from: naomifelixwoo

=760 ft

Step-by-step explanation:

h=16t^2+126t

Let t=4

h = 16 (4)^2 +126(4)

h = 16*16 +126(4)

  =256+504

   =760 ft

ansver
Answer from: rutza

236ft.

Step-by-step explanation: To solve the given problem, we need to substitute the given time (4 seconds) in the equation to calculate the height of the object with an initial velocity of 129ft per sec. The substitution is shown as follow:

h=-16^{2} +123t

h=-16^{2} +123(4)

h=-256+492

h=236ft.

The height of the object after 4 seconds is 236ft.

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Answer from: aedmund1225

8 centermeters

Step-by-step explanation:

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Answer from: okokjade

This problem can be solved directly by neglecting the initial velocity given. All we have to do is to plug in t = 4 in the given equation. That is:

h = -16^2 + 123 * 4

h = 236 ft

ansver
Answer from: ernest214

You are given a function h(t)=-16t^2+127t. This function shows you the dependence of height from time.

To find the height of the object after 4 seconds, you should substitute t=4 into the function expression:

 h(4)=-16\cdot 4^2+127\cdot 4=-16\cdot 16+508=-256+508=252\ ft.

the height of the object after 4 seconds will be 252 ft.

ansver
Answer from: saraderrico
After 4 seconds
h(4) = -16(4)^2 + 126(4) = -16(16) + 504 = -256 + 504 = 248 feet.
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Answer from: PanjiUR9220
I would think it is
h=-16t^2+124t
after 4 seconds or when t=4 find h
h=-16(4^2)+124(4)
h=-16(16)+496
h=-256+496
h=240

height is 240 feet
ansver
Answer from: kate3887
This equation should be written h(t) = -16t^2 + 129t.  After 4 sec, the height of this object is

h(4) = -16(4)^2 + 129(4) = -256 + 516 = 260 feet.
ansver
Answer from: kyreesegordon
To find the height of the object after 4 seconds, just input the 4 where t is located.

So
h=-16t^2 = 129t
h=-16(4)^2 = 129(4)
Now just solve for h

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