# What is the length of the shortest side of a triangle that has vertices at (-3, -2), (1, 6), and (5, 3)?

5

Step-by-step explanation:

Figuring the short side, it becomes a nice 3, 4, 5 triangle

so the short side is 5 units.

Hope this helped

:)

5

Step-by-step explanation:

We can use the distance formula with 3 different vertices to figure out the shortest of the three sides.

The distance formula is

Where (x_1,y_1) is the first points and (x_2,y_2) is the second set of points, respectively.

Now let's figure out the length of 3 sides.

1. The length between (-6,-5) & (-5,6):

2. The length between (-6,-5) & (-2,2):

3. The length between (-5,6) & (-2,2):

Thus, length of the shortest side is 5.

The length of shortest side is

Step-by-step explanation:

Let

we know that

the formula to calculate the distance between two points is equal to

step 1

Find the distance AB

substitute in the formula

step 2

Find the distance BC

substitute in the formula

step 3

Find the distance AC

substitute in the formula

Compare the length sides

The length of shortest side is

is given by

i) the distance between points (-2, 5) and (-2, -7) is:

units

ii) the distance between points (-6, -4) and (-2, -7) is:

units

iii) the distance between points (-2, 5) and (-6, -4) is:

units.

the shortest distance is the distance between points (-6, -4) and (-2, -7)

B(1,-2) C(0,-6)

Now plug the points into the distance formula

Distance= √(x2-x1)² + (y2-y1)²

Distance= √(0-1)² + (-6+2)²

Distance= √(-1)² + (4)²

Distance= √1 + 16

Distance= √17

Distance is approx 4.12