 , 22.06.2019 21:00 batista68

# What is the length of the shortest side of a triangle that has vertices at (-3, -2), (1, 6), and (5, 3)? )-2,2)

Explanation: 5

Step-by-step explanation:

Figuring the short side, it becomes a nice 3, 4, 5 triangle

so the short side is 5 units.

Hope this helped

:) 5

Step-by-step explanation:

This is a 3, 4, 5 triangle 5

Step-by-step explanation:

We can use the distance formula with 3 different vertices to figure out the shortest of the three sides.

The distance formula is Where (x_1,y_1) is the first points and (x_2,y_2) is the second set of points, respectively.

Now let's figure out the length of 3 sides.

1. The length between (-6,-5) & (-5,6): 2. The length between (-6,-5) & (-2,2): 3. The length between (-5,6) & (-2,2): Thus, length of the shortest side is 5. a

Step-by-step explanation: The length of shortest side is Step-by-step explanation:

Let we know that

the formula to calculate the distance between two points is equal to step 1

Find the distance AB substitute in the formula   step 2

Find the distance BC substitute in the formula   step 3

Find the distance AC substitute in the formula   Compare the length sides

The length of shortest side is  Given 2 point P(a, b) and Q(c, d), the distance |PQ|

is given by i) the distance between points (-2, 5) and (-2, -7) is: units

ii) the distance between points (-6, -4) and (-2, -7) is: units

iii) the distance between points (-2, 5) and (-6, -4) is: units.

the shortest distance is the distance between points (-6, -4) and (-2, -7) I think the answer is 3  The distance of BC is going to be the shortest side. (see attached picture)
B(1,-2) C(0,-6)

Now plug the points into the distance formula
Distance= √(x2-x1)² + (y2-y1)²
Distance= √(0-1)² + (-6+2)²
Distance= √(-1)² + (4)²
Distance= √1 + 16
Distance= √17
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What is the length of the shortest side of a triangle that has vertices at (-3, -2), (1, 6), and (5,...

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