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Mathematics, 22.06.2019 21:00 rosieanneanney

Ricardo has 2 cases of video games with the same number of games in each case. he gives 4 games to his brother. ricardo has 10 games left. how many games wee in each case?

Answers

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Answer from: shanedietz44ovi6rb

7 games

Step-by-step explanation:

Ricardo has 2 cases with x number of games in each. This means 2x is the amount of video games in both. He gives away 4. He now has 2x-4 and has 10 left. This is 2x-4=10. Solve for x.

2x - 4 = 10

2x = 14

x=7

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Answer from: emily200705
10+4=14, 14/2=7, 7 would be the answer
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Answer from: theyenvylexii
10+4=14

14÷2=7

there were 7 games in each case
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Answer from: htorres2p8urw0
12 because you split the 4 from the two boxes.
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Answer from: S917564
7 games in each case
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Answer from: tonypewitt
7 games were in each case. 10 +4=14
14 divided by 2 cases = 7

7 games were in each case
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Answer from: XxpinkgothicxX
total = 10 + 4 = 14

games per case = total/2
= 14/2
= 7
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Answer from: fathimasaynas2384

7

Step-by-step explanation:

The total number of video games he had to begin with is 4+10=14.

Divide the total games by 2 (cases) and you get 7 games in each case

ansver
Answer from: LillyPrince

7

Step-by-step explanation:

Both the cases contained equivalent no. of video games so after he gave 4 games and was left with 10 afterwards so we can conclude that he had 14 games in total in the first place and if we divide it by 2 for the purpose of distributing the games evenly in both the cases we are left over with 7

ansver
Answer from: esilvar4378
First, you have to add 10+4=14, then you have to divide 14 by 2 to get 7

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