Test the conditional statement and its converse to determine whether the following biconditional is true. |x| > 0 if and only if x > 0 a. it is true because at least one part of the biconditional is true. b. it is true because both parts of the biconditional are true. c. it is false because both parts of the biconditional are false d. it is false because at least one part of the biconditional is false.
The bi-conditional is false.
We are told:
1. If a number is divisible by 6 then it is divisible by three, AND
2. If a number is divisible by 3 then it it divisible by six.
Both conditions must be true for the original bi-conditional statement to be true.
Statement 2 can easily be disproved by the counter example:
15 is divisible by 3 but is not divisible by six.
Which is why the given bi-conditional is FALSE.