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Mathematics, 22.06.2019 21:00 ineedhelp2285

What’s the molar mass of sulfur trioxide so3

Answers

ansver
Answer from: bskyeb14579

80.066 g/mol

Step-by-step explanation:

ansver
Answer from: 4804344130

18,01528 g/mol

110,98 g/mol

159,609 g/mol

169,87 g/mol

98,079 g/mol

Explanation:

ansver
Answer from: thatlostgirl7740

The volume of NaOH needed to add is 12.35 mL

Explanation:

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of sulfurous acid = 0.0865 g

Molar mass of sulfurous acid = 82.079 g/mol

Volume of solution = 250 mL

Putting values in above equation, we get:

\text{Molarity of sulfurous acid}=\frac{0.0865\times 1000}{82.079\times 250}\\\\\text{Molarity of sulfurous acid}=0.0042M

To calculate the volume of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=0.0042M\\V_1=250mL\\n_2=1\\M_2=0.1700M\\V_2=?mL

Putting values in above equation, we get:

2\times 0.0042\times 250=1\times 0.1700\times V_2\\\\V_2=\frac{2\times 0.0042\times 250}{1\times 0.1700}=12.35mL

Hence, the volume of NaOH needed to add is 12.35 mL

ansver
Answer from: HighSchool97654

3.002 moles

Explanation:

Conversion factor: 96.25 g S x (1 mol S/32.06 g S)

Divide 96.25/32.06 = 3.002

ansver
Answer from: claudia3776

32.07 u

Explanation:

Sulfur is S on the periodic table! If you look at S on the periodic table its molar mass will show 32.065 u but because your question says round to 2 decimal places, round the 6 to a 7! The units are 'u' which is the dalton or unified atomic mass unit which can either be Da or u

Hope this helps!

ansver
Answer from: annamcveigh50

32.11 g/mol

Explanation:

Given;

32S => 91.65%, 31.97g/mol

33S => 2.4%, 32.97g/mol

34S => 5.95%, 33.97g/mol

The molar mass of sulfur in the sample is the weighted average of the molar masses of its isotopes based on the percentage abundances.

i.e

molar mass = (\frac{91.65}{100} x 31.97) + (\frac{2.4}{100} x 32.97) + (\frac{5.95}{100} x 33.97)

molar mass = (0.9165 x 31.97) + (0.024 x 32.97) + (0.0595 x 33.97)

molar mass = (29.30) + (0.79) + (2.02)

molar mass = 32.11g/mol

Therefore the molar mass of sulfur in the sample is 32.11 g/mol

ansver
Answer from: shayleewright

80.07 g/mol

Explanation:

ansver
Answer from: jazzwok

80.07 g/mol

Explanation:

Sulfur's g/mol = 32.07

Oxygen's g/mol = 16.00

32.07 + 16.00(3) = 80.07 g/mol

ansver
Answer from: ian2006huang

98.09g/mol

Step-by-step explanation:

the molar mass of any compound is derived by the  multiplying the individual atomic masses of each of the elements present in the compound by the number of atoms each element has and then adding each of the values together

for H₂SO₄ (sulphuric acid)

elements present are hydrogen, sulphur and oxygen

atomic mass of hydrogen = 1.00784

atomic mass of sulphur =32.065

atomic mass of oxygen = 15.999

the acid contains 2 atoms of hydrogen, one atom of sulphur and 4 atoms of oxygen

∴molar mass of H₂SO₄ = (2 × atomic mass of hydrogen) + atomic mass of                    sulphur + (4 × atomic mass of oxygen)

= (2 × 1.00784) + 32.065 + (4 × 15.999)

= 2.01568 + 32.065 + 63.996

= 98.09g/mol

ansver
Answer from: heysorryguys

Explanation:

i) (18 X 336) air/h = 6048 air/h

Engine speed = 2500 rpm; Capacity of diesel = 800 ppm

∴ 2500/800 = 3.125 kg/pm

Mass flow rate = (3.125 X 6048) Kg/h/pm =18900 Kg/h/pm

ii) Mass flow rate = 32 X 4/1000 X 2500 = 320 Kg/h/pm

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