20 ! let f(x)=1/x and g(x)=x^2-7x. what two numbers are not in the domain of f°g? separate your answes with a comma.

Hello from MrBillDoesMath!

x = 0, 7

Discussion:

f(g(x)) =

f ( x^2-7x) =

1/ ( x^2 - 7x)

The points NOT in the domain are those where the denominator,  x^2 - 7x = 0.

x^2 - 7x   = 0       =>       factor x from each term

x(x-7) = 0            =>        one or both terms must each 0

x = 0 or x =7

Thank you,

MrB

126 maybe. sorry

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation: