The sum of 6 consecutive integers is 519. what is the third sequence?

X=84

Step-by-step explanation:

let x be the first integer, then

:

x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) = 519

:

6x + 15 = 519

:

6x = 504

:

x = 84

dd

step-by-step explanation:

dd

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)