Aparabola passes through the points (–5, –10) and (5, –10), and the vertex is located at (0, 0). find the equation of the parabola. a. x^2=-5/2y b. x^2=-5/8y c. x^2=-5/32y d. y^2=-5/2x

  A.  x^2 = -5/2y

Step-by-step explanation:

The parabola has its vertex at (0, 0) and opens downward, so its equation can be of the form ...

   x^2 = ay . . . . . for some negative constant "a"

We can find "a" by putting the values of one of the points into this equation and solving for "a".

  (-5)^2 = a(-10)

  25/(-10) = a = -5/2

The equation is ...

  x^2 = -5/2y

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