What is the equation of the line that passes through the (-2,-3) points and (4,-5) ?

y = -1/3 -11/3

Step-by-step explanation:

We can find the slope of the line using the two given points

m = (y2-y1)/(x2-x1)

   = (-5--3)/ (4--2)

   = (-5+3)/(4+2)

  =-2/6

 = -1/3

Then we can use point slope form to calculate the equation of the line

y-y1 = m(x-x1)

y--3 = -1/3(x--2)

y+3 = -1/3(x+2)

This is in point slope form

Distribute the -1/3

y+3 = -1/3x -2/3

Subtract 3 from each side

y+3-3 = -1/3x -2/3 -3

y = -1/3x -2/3 -9/3

y = -1/3 -11/3

This is in point slope form

step-by-step explanation:

4 and 5)16.97 or 12√2

6)15.59 or 9√3

7)y = 15.59 or 9√3     x =27

8)17.80