Charlene puts together two isosceles triangles so that they share a base, creating a kite. the legs of the triangles are 10 inches and 17 inches, respectively. if the length of the base for both triangles is 16 inches long, what is the length of the kite’s other diagonal? 6 inches inches inches 21 inches

21 inches is the correct answer on edg.

Refer to the attached figure. We know that AB is 16 inches. We also know that AD=BD=10 and AE=BE=17

We're interested in DE, which we can compute as CD+CE

To compute CD, we can observe that ACD is a right triangle, and that AC is 8 inches long (it's half the base) and AD is 10 inches long (given).

So, by Pythagorean's theorem, we have

Similarly, we have

So, we have

answer is because 4×10=40

and 98×4= is 392

40,392