In the triangle below what is the length of the hypotenuse

B 6

Step-by-step explanation:

sin theta = opposite / hypotenuse

sin 30 =3 /hypotenuse

Multiply by the hypotenuse on each side

hypotenuse * sin 30 = 3

Divide by sin 30

hypotenuse = 3/sin 30

hypotenuse = 6

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine