State the quotient and remainder when the first polynomial is divided by the second. 3x^4-3x^3-11x^2+6x-1; x^3+x^2-2

, and . Subtracting this from the numerator leaves a remainder of

, and . Subtracting this from the previous remainder gives a new remainder of

has no factors of , so we stop here. Then

Q = 3x – 6; R = -5x² + 12x - 13

Step-by-step explanation:

One way is to use long division.

                 3x    - 6                                                

x³ + x² - 2) 3x⁴  - 3x³ - 11x² +    6x -  1

                 3x⁴ + 3x³           -    6x    

                       -  6x³ - 11x²  + 12x  -  1

                       -  6x³ - 6x²            + 12

                                 - 5x²  + 12x  - 13

Quotient = 3x – 6; Remainder = -5x²+ 12x - 13

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

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step-by-step explanation: