For the information h(x)=2^(6x+7), find two functions f(x) and g(x) such that h(x)=f(g(x))

f(x) = 2^x; g(x) = 6x+7

Step-by-step explanation:

h(x)=2^(6x+7) can be decomposed as follows:

f(x) = 2^x and g(x) = (6x+7)

Note that g(x) = (6x+7) becomes the input to f(x):

f(x) = 2^x  => f( g(x) ) = 2^(6x+7).

This is called a "composite function."

Answers:  f(x) = 2^x; g(x) = 6x+7

2

step-by-step explanation:

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1