The average test scores for a particular test in algebra was 84 with a standard deviation of 5. what percentage of the students scored higher than 89%? explain your answer.

The percentage of the students scored higher than 89% is 15.87%

Step-by-step explanation:

we are given

The average test scores for a particular test in algebra was 84

so, mean is 84

a standard deviation of 5

so,

we have

x=89

now, we can use z-score formula

now, we can plug values

now, we can use calculator

and we get

So,

The percentage of the students scored higher than 89% is 15.87%

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: