Acampus survey of owls indicates that 7% are charming, 4% are modest, and 3% are both charming and modest. find the probability that an owl is modest, given that he/she is charming. given that a student isn't modest, what is the probability that they are not charming?

P(modest | charming) = 0.4286

P(not charming | not modest) = 0.896

Step-by-step explanation:

This is a conditional probability problem.

Let A and B be two dependent events, then:

The probability of A given B is written as:

P (A | B) =

So:

The probability that an OWL is modest given that he/she is charming is:

P (modest | charming) =

P (modest | charming) =

P (modest | charming) = 0.4286

Then, the probability that a student is not modest is:

The probability that a student is not charming and not modest is:

So:

P(not charming | not modest) =

P(not charming | not modest) =

P(not charming | not modest) = 0.9583

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )

the solution, from the graphing of the two lines, is (3,2), i.e., x = 3, y = 2.