All of the following points lie on the graph of y = 3 x except (0, 1) (1, 3) (2, 6) (3, 27)

The answer is (0,1) and (3,27)

Step-by-step explanation:

Given points (0,1)(1,3)(2,6)(3,27)

and equation of line y=3x [1]

The points that will satisfy the equation lie on it

Taking (0,1) : Putting it in [1]  It does not satisfy it as 3*0=0

Taking (1,3): When we put it in [1] 1*3=3

i.e. it satisfy the equation

Taking (2,6): When we put it in [1] 2*3=6

i,e, it satisfy the equation

Taking (3,27): On putting it in [1] 3*3= 9

i.e. it does not satisfy the equation

Hence (0,1) (3,27) does not lie on y=3x

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts