Segment wx is shown. explain how you would construct a perpendicular bisector of wx using a compass and a straightedge.

You can use a compass and set its angle such that it the radius of the circle that it will draw is less than that of WX's length but longer than its half. Use it to make 4 arcs.

Making 4 arcs (2 arcs up and down from W and 2 arcs up and down from X which intersect previous two arcs) with circle of radius smaller than the length of  WX will give two points on perpendicular bisector.

The construction steps are as follows:

Let the line segment to be bisected(divided in two equal parts) by a perpendicular line(that perpendicular bisecting line is called perpendicular bisector of the given line segment) be WX

Using the above method, we get the perpendicular bisector of WX  shown in the below attached figure.

Thus,

Making 4 arcs (2 arcs up and down from W and 2 arcs up and down from X which intersect previous two arcs) with circle of radius smaller than the length of  WX will give two points on perpendicular bisector.

Learn more about constructing perpendicular bisector here:

link

See description below.

Step-by-step explanation:

The given line segment WX is shown.

To construct a perpendicular bisector of WX, do the following;

1. Place the compass tip at point W and open the compass to more than half the radius of segment WX.

2. Draw an arc up and another arc below the line segment.

3. Maintaining the same radius, stand at point X and draw an arc above to intersect the first arc, and another arc below also to intersect the first one.

4. Using a straight edge, draw a straight line through the intersections of the pairs of arcs.

i think 1: 2

step-by-step explanation:

answer: 48

just remember to use pemdas:

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