If the sum of three consecutive numbers is 210, what is the largest of the three numbers?

n = 71

Step-by-step explanation:

We take three consecutive numbers n-1, n and n+1.

the sum of this three is

n-1 + n + n+1 = 210 => 3n = 210  => n = 210/3 = 70

The largest of the three numbers is

n+1 = 70 + 1 = 71

God with you!!!

it would take 7/10 of an hour too fill the pool.

step-by-step explanation:

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!