Two hikers start from the same point and hike in opposite directions around a lake whose shoreline is 15 mi long. one hiker walks 0.5 mph faster than the other hiker. how fast did each hiker walk if they meet in 2 h?

Step-by-step explanation:

Let the distance the slower hiker travels=d,

the distance the faster hiker travels=15-d (Since, the sum of the distances they walk is 15mi).

Let the speed of the slower hiker in mi/hr=s,

the speed of the faster hiker=s+0.5

Now, equation for the slow hiker:

                                                           (1)

and equation for the faster hiker:

                                                      (2)

Now, substituting the equation (1) in equation (2),

and

The speed of the slower hiker is and The speed of the faster hiker is .

horizontal translation of 2 units in the positive x direction

followed by

vertical translation of 3 units in the positive y direction

answer: b.36 feet

step-by-step explanation: