In 2003, the owl population p in a park was measured to be 340. by 2007, the population was measured again to be 285. the population changes linearly. let the input t be years since 2003. a.) find a formula for the owl population, p. let the input be years t since 2003. b.) what does your model predict the park’s owl population to be in 2019?

y = -13.75x + 340

120 owls in 2019

Step-by-step explanation:

To find the population in a future year, use the formula y=mx+b since it changes linearly.

So over 4 years the owl population changed from 285-340=-55. Divide by 4 and this is a yearly change of -13.75. This is m.

The y-intercept is the starting point known as b in the equation. Here it is 340.

So the equation is y=-13.75x+340.

In 2019, t=16 so y=-13.75(16)+340 = 120.

we need more info to solve this

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts