Question 4: two equations are shown: equation 1: 3/4 (x−12)=12equation 2: 3/4 y−12=12solve each equation. then, enter a number in each box to make this statement true. the value of x is: the value of y is: asap it is due today

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

step-by-step explanation: