Since bc is parallel to de, triangles abc and ade are similar. what are the lengths of the unknown sides? a. ac = 14 cm; ce = 8 cm b. ac = 12 cm; ce = 7 cm c. ac = 5 cm; ce = 10 cm d. ac = 10 cm; ce = 5 cm

Option D. AC= 10 cm and CE= 5 cm

Step-by-step explanation:

From the given figure two triangles ΔABC and ΔADE are similar and two lines BC║DE.

From these similar triangles we know

Therefore

Or AC=

Now from pythagoras theorem

AE = √(AD²+ED²) = √(12²+9²) = √(144+81) =√225 = 15 cm

Since we know side AC =

                                        =

                                        = 10 cm

Therefore AC = 10 cm and AE = 15cm and CE = (15-10) = 5 cm

i dont know nkw

step-by-step explanation:

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18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.