Which is a correct expansion of(4x+1)(2x^2-2)and just to let you know this is a times symbol × and this is an xa.4x×2x^2+4x×(-2)+1×4x+1×(-2)b.4x× 2x^2+4x×(1)+1×2x^2+1×(-2)c.4x×2x^2+ 4x×(-2)+1×2x^2+1×(-2)

sorry can't

step-by-step explanation:

i googled though and something came up but it was in science langueage not common english sooo

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.