Mathematics, 24.06.2019 13:30 chloedfite2978
Find the equation of a circle with center (6,-2) and radius 12
Answers: 1
![\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{6}{ h},\stackrel{-2}{ k})\qquad \qquad radius=\stackrel{12}{ r} \\[2em] [x-6]^2+[y-(-2)]^2=12^2\implies (x-6)^2+(y+2)^2=144](/tpl/images/0011/9909/07d74.png)
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