Parallelogram abcd is a rectangle. ac=6y−1 bd=4y+13 what is the value of y? enter your answer in the box. y= a rectangle a b c d. side a b and side c d are parallel. side a d and b c are parallel. diagonal b d and a c intersect each other at a point labeled as x.

The value of y is: 7

Step-by-step explanation:

The figure of the rectangle ABCD is attached to the answer.

We are given that Parallelogram ABCD is a rectangle.

AC=6y−1

BD=4y+13

Diagonal BD and AC intersect each other at a point labeled as X.

Also we know that: The two diagonals of a rectangle are equal in length and bisect each other.

i.e. length of AC=BD

Hence 6y-1=4y+13

⇒   6y-4y=13+1

 ⇒  2y=14

  ⇒  y=7

Hence, AC=6×7-1=42-1=41

      BD=4×7+13=41

Hence, the value of y is 7.

step-by-step explanation:

we have

using a graphing tool

see the attached figure

this is a quadratic equation (vertical parabola) open up

the vertex is a > vertex

the domain of the function is all real > interval (-∞,∞)

the range of the function is the > [-6.125,∞)

the function has two x->   and

the function is increasing over the > (0.25,∞)

the function is decreasing over the > (-∞,0.25)